Exponential Distribution: Probability Density Functions

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In this article, explore the world of continuous probability functions with exponential distribution. Learn to model and analyze random phenomena with this versatile mathematical tool.

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What Is the Exponential Distribution?

The Exponential Distribution is a continuous probability distribution used to model the time between events in a Poisson Process. It describes situations where we want to calculate:

- The time until the next failure of a system.

- The time between customer arrivals in a queue.

- The duration of phone calls.

It is especially useful because it has the memoryless property, meaning the probability of an event occurring in the future does not depend on the time already elapsed.

Formula of the Exponential Distribution

The probability density function (PDF) of the exponential distribution is given by:

\[ f(x) = \lambda e^{-\lambda x} \quad \text{for} \quad x \geq 0 \]

Where:

- \( \lambda \) (lambda) = occurrence rate (events per unit of time).

- \( x \) = time (or space) until the next event.

The cumulative distribution function (CDF), which calculates \( P(X \leq x) \), is:

\[ F(x) = 1 - e^{-\lambda x} \]

Graph of the Exponential Distribution for different values of \( \lambda \)
Graph of the Exponential Distribution for different values of \( \lambda \)

Real-Life Examples

Example 1: Time between system failures

- Situation: A server fails, on average, every 500 hours (\( \lambda = \frac{1}{500} \)).

- Question: What is the probability that the server will fail before 300 hours?

Solution:

\[ P(X \leq 300) = 1 - e^{-\frac{1}{500} \cdot 300} = 1 - e^{-0.6} \approx 1 - 0.5488 = 0.4512 \quad (45.12\%) \]

Example 2: Time between customer arrivals

- Situation: Customers arrive at a bank, on average, every 10 minutes (\( \lambda = \frac{1}{10} \)).

- Question: What is the probability that the next customer will arrive in more than 15 minutes?

Solution:

\[ P(X > 15) = e^{-\frac{1}{10} \cdot 15} = e^{-1.5} \approx 0.2231 \quad (22.31\%) \]

Example 3: Duration of phone calls

- Situation: Calls in a call center last, on average, 4 minutes (\( \lambda = \frac{1}{4} \)).

- Question: What is the probability that a call will last less than 2 minutes?

Solution:

\[ P(X \leq 2) = 1 - e^{-\frac{1}{4} \cdot 2} = 1 - e^{-0.5} \approx 1 - 0.6065 = 0.3935 \quad (39.35\%) \]

Relationship between Poisson and Exponential

- Poisson models the number of events in a fixed interval.

- Exponential models the time between events (when events follow Poisson).

If events occur at rate \( \lambda \) in Poisson, then the time between events follows an Exponential distribution with parameter \( \lambda \).

When to Use the Exponential Distribution?

Use it when:

1. The process is continuous in time/space.

2. Events occur independently and at a constant rate.

3. You are interested in the time between events, not their count.

Application examples:

- Time until the next failure of an electronic component.

- Time between ship arrivals at a port.

- Useful life of products before they show defects.

Exercises

1. System failures:

- A computer fails, on average, every 1000 hours. What is the probability that it fails before 500 hours?

2. Bus arrival:

- Buses arrive at a stop, on average, every 15 minutes. What is the probability that the next bus arrives in more than 20 minutes?

3. Cashier service:

- A supermarket cashier serves, on average, one customer every 5 minutes. What is the probability that the next service takes less than 3 minutes?

4. Lifetime of light bulbs:

- Light bulbs burn out, on average, after 8000 hours. What is the probability that a light bulb lasts more than 10,000 hours?

5. Phone calls:

- Calls in a call center last, on average, 6 minutes. What is the probability that a call lasts between 4 and 8 minutes?

6. Failure Time with Multiple Components

A system has 3 independent components, each with failure time following an Exponential distribution (\( \lambda = 0.01 \) hours⁻¹). The system fails if at least 2 components fail.

- Question: What is the probability that the system fails within the first 100 hours? (Use the exponential distribution to find the failure probability and then the binomial distribution to add the probabilities of at least 2 successes)

Answer Key

1. 39.35%

2. 26.42%

3. 45.12%

4. 28.65%

5. 24.72%

6. 69.35%